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-2p^2+12p+110=0
a = -2; b = 12; c = +110;
Δ = b2-4ac
Δ = 122-4·(-2)·110
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-32}{2*-2}=\frac{-44}{-4} =+11 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+32}{2*-2}=\frac{20}{-4} =-5 $
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